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Use "known" label if possible when making new grid filters

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Lance Edgar 2018-06-14 12:04:35 -05:00
parent 7c46f10dd1
commit 8428790001
1 changed files with 2 additions and 0 deletions
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2
tailbone/grids/core.py
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@ -159,6 +159,8 @@ class Grid(object):
if len(args) == 1 and args[0] is None: if len(args) == 1 and args[0] is None:
self.remove_filter(key) self.remove_filter(key)
else: else:
if 'label' not in kwargs and key in self.labels:
kwargs['label'] = self.labels[key]
self.filters[key] = self.make_filter(key, *args, **kwargs) self.filters[key] = self.make_filter(key, *args, **kwargs)
def remove_filter(self, key): def remove_filter(self, key):